CaC2 + 2H2O → C2H2 + Ca(OH)2
16g = 0.25 moles CaC2
18g = 1.0 mole H2O
Since CaC2 is the limiting reactant, you will get 0.25 moles Ca(OH)2
That is 18.5 grams
16 gram of CaC2 and 18 gram of H2O were mixed in the given reaction,
CaC2 + 2H2O it gives C2H2 + Ca(OH)2.
A, what mass of Ca(OH)2 is formed?
2 answers
of Ca(OH)2 formed (0.25 mol x 74 g/mol). Therefore, 18.5 grams of Ca(OH)2 is formed.