16−3(d+4)

=
9d−8

16 + −3 ( d + 4)
=
9d−8

16 +
+ ?
=
9d−8

1 answer

To solve the equation \(16 - 3(d + 4) = 9d - 8\), let's first simplify the left side.

  1. Distribute \(-3\) on the left: \[ 16 - 3(d + 4) = 16 - 3d - 12 \] This simplifies to: \[ 4 - 3d \]

  2. Now we have: \[ 4 - 3d = 9d - 8 \]

  3. Next, add \(3d\) to both sides: \[ 4 = 12d - 8 \]

  4. Now, add \(8\) to both sides: \[ 12 = 12d \]

  5. Finally, divide by \(12\): \[ d = 1 \]

Thus, the solution to the equation \(16 - 3(d + 4) = 9d - 8\) is \(d = 1\).

For the expression \(16 + -3(d + 4) = 9d - 8\), it simplifies to the same equation as above, leading to the same result.

Now, for the equation \(16 + + ? = 9d - 8\), if we let \(? = -3(d + 4)\), then it holds:

  1. \(16 + -3(d + 4) = 9d - 8\)

This equals: \[ 16 - 3(d + 4) = 9d - 8 \]

So, \(? = -3(d + 4)\) is the appropriate completion of the equation where \(d = 1\).

To conclude:

  • The value of \(d\) that satisfies the original equations is \(d = 1\).
  • The missing term \(?\) in your expression \(16 + + ? = 9d - 8\) is \(-3(d + 4)\).