First, we need to find the moles of sodium chloride present in the solution.
To do this, we use the formula:
moles = mass / molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
moles of NaCl = 0.15g / 58.5 g/mol = 0.00256 mol
Next, since each molecule of NaCl contains 1 chloride ion, the concentration of chloride ions in moles per liter is the same as the concentration of NaCl.
Concentration of chloride ions = 0.00256 mol / 0.12 L = 0.0213 mol/L
Therefore, the concentration of chloride ions in the solution is 0.0213 mol/L.
.15g of sodium chloride was dissolved in 120cm3 of distilled water. Calculate the
concentration of chloride ions in moles per litre. (Na = 23, Cl = 35.5)
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