Question

a body is moving in a vertical circle such that the velocities of body at different points are critical the ratio of velocities of body at angular displacements 60° 120° from lowest point is √2:1

Answer 1

a body is moving in a vertical circle such that the velocities of body at different points are critical the ratio of velocities of body at angular displacements 60° 120° from lowest point is
And =√2:1

Answer 2

height h at angle T = R - R cos T
height h at 60 deg = R/2
height h at 120 deg = 3 R/2

kinetic energy
(1/2)mv^2 + m g h = constant

at 60 deg
(1/2)v1^2 + g(R/2)=(1/2)v2^2 + g(3R/2)
(v1^2 -v2^2) = 2 g R
if it just makes it to the top then
(1/2) m v1^2 = m g * 2R
v1^2 = 4 g R

(4 g R - v2^2 ) = 2 g R
v2^2 = 2 g R
v1^2/v2^2 = 4 g R / 2 g R
V1/V2 = sqrt 2 / 1

Answer 3

It's absolutely wrong because we need to find both 60degrees and 120degress

Answer 4

How the hell its wrong!!!
It's perfectly explained!

Anyway thanks for that dude who posted the right one!!!!!