Question

A see-saw 3.76 meters long perfectly balances on its own at its center. Two children get on the see-saw. One, weighing 345 N, sits at the left hand end. The other, sits 25.0 cm in from the right hand end. The see-saw is perfectly balanced with the children sitting in these locations. What is the weight of the child on the right?

Answer 1

sum moments about the pivot
W*3.76/2-345(3.76/2-.25)=0
solve for Weight W

Answer 2

F1 * d1 = F2 * d2.
345 * 3.76/2 = F2 * (3.76/2-0.25).
F2 = ?.