Asked by Jay
Two missiles, 2420 km apart, are launched at the same time and are headed towards each other. They pass after 1.5 hours. The average speed of one missile is twice that of the other. What is the average speed of each missile?
Answers
Answered by
Steve
If the slower's speed is s km/hr, then their combined speed of approach is s+2s = 3s
So, since distance = speed * time,
3s * 3/2 = 2420
So, since distance = speed * time,
3s * 3/2 = 2420
Answered by
Henry
d1 + d2 = 2420.
V1*T1 + V2*T2 = 2420.
V2 = 2V1, T1 = T2 = 1.5 h.
V1*1.5 + 2V1*1.5 = 2420, V1 = ?.
V2 = 2V1.
V1*T1 + V2*T2 = 2420.
V2 = 2V1, T1 = T2 = 1.5 h.
V1*1.5 + 2V1*1.5 = 2420, V1 = ?.
V2 = 2V1.
Answered by
Tess tickles
Gape Horn