Asked by Jay
                Two missiles, 2420 km apart, are launched at the same time and are headed towards each other. They pass after 1.5 hours. The average speed of one missile is twice that of the other. What is the average speed of each missile?
            
            
        Answers
                    Answered by
            Steve
            
    If the slower's speed is s km/hr, then their combined speed of approach is s+2s = 3s
So, since distance = speed * time,
3s * 3/2 = 2420
    
So, since distance = speed * time,
3s * 3/2 = 2420
                    Answered by
            Henry
            
    d1 + d2 = 2420.
V1*T1 + V2*T2 = 2420.
V2 = 2V1, T1 = T2 = 1.5 h.
V1*1.5 + 2V1*1.5 = 2420, V1 = ?.
V2 = 2V1.
    
V1*T1 + V2*T2 = 2420.
V2 = 2V1, T1 = T2 = 1.5 h.
V1*1.5 + 2V1*1.5 = 2420, V1 = ?.
V2 = 2V1.
                    Answered by
            Tess tickles 
            
    Gape Horn
    
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