Carmen is choosing a

3
-letter password from the letters A, B, C, and D. The password cannot have the same letter repeated in it. How many such passwords are possible?

1 answer

there are 4 choices for the 1st letter

since that letter is used, there are only 3 choices for the 2nd letter.

So, extending that logic, the number of possible passwords is 4*3*2 = 24