Asked by observation
A sphere of mass 0.4kg moving on a smooth billiard table hit a stationary sphere of mass 0.8kg and was brought to rest. Calculate the velocity at which the second sphere tends to move and loss in K.E energy
Answers
Answered by
bobpursley
momentum is conserved,
.4V=.8v'
v'=1/2 V
new KE= 1/2 .8 (v'^2)1/2*.8*(1/2 v)^2
= 1/2*.8*1/4* v^2
loss of KE= old ke-new ke
= .4/2 v^2-.1/8 v^2
.4V=.8v'
v'=1/2 V
new KE= 1/2 .8 (v'^2)1/2*.8*(1/2 v)^2
= 1/2*.8*1/4* v^2
loss of KE= old ke-new ke
= .4/2 v^2-.1/8 v^2
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