Question

Inside a box(mass "M"), a light string "X" is atthached to it's bottom and the other end of the string is attached to a mass "m"(this makes a pendulum).

This system is attached to the point O(the center of gravity of the system), by a string " Y" and moved with constant speed of "v" in a vertical circle of radius "R"

Find the tensions of the strings X and Y,when the system is in the right hand side of the point O.(The right hand side end of the circular motion, let's call it point B)

At the point B,if we apply F=ma towards the center (point O) considering the system,



Let's call the tension of the string Y at the point B as Ty

Ty - (M+m)v^2/R = (M+m)*0
Ty=(M+m)v^2/R

Am I correct and how do we find the tension of the string X?

Answer 1

*Ty - (M+m)v^2/R + (M+m)g = (M+m)*0

Ty= (M+m)[(v^2/R) - g ]