Use x=-1/2 in the MacLaurin series for e^x to approximate 1/sqrt (e) to four decimal places.
So far I have
|f^n(0)/n! (1/sqrt(e)-1/2)^n)| </= 1/10^4, but I don't know what to do from here.
So far I have
|f^n(0)/n! (1/sqrt(e)-1/2)^n)| </= 1/10^4, but I don't know what to do from here.