Asked by Josh
a and b are perpendicular vectors.a=(2i+3j) and b=ti+dj(d>0 and i and j are unit vectors) and |b|=1
Find t and d?
I know we have to use the cross product here.
a.b=|a||b|*cos(π/2)
(2i+3j)(ti+dj)= √13*1*0
2t+3j=√13*0
How do we find t and d?
Find t and d?
I know we have to use the cross product here.
a.b=|a||b|*cos(π/2)
(2i+3j)(ti+dj)= √13*1*0
2t+3j=√13*0
How do we find t and d?
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