Asked by Daisymerolling
                The prime factorization of 360 can be written in the form 
(a^m)(b^n)(c^r). What is the valye of a+b+c-mnr
            
        (a^m)(b^n)(c^r). What is the valye of a+b+c-mnr
Answers
                    Answered by
            Reiny
            
    go ahead, express 360 in that form.
360 = 2* 180
= 2*2*90
= 2*2*2*45
= 2*2*2*3*3*5
= 2^3 * 3^2 * 5^1
so , what do you think ?
    
360 = 2* 180
= 2*2*90
= 2*2*2*45
= 2*2*2*3*3*5
= 2^3 * 3^2 * 5^1
so , what do you think ?
                    Answered by
            daisymerolling
            
    5 is not one of the choices.
    
                    Answered by
            Reiny
            
    You are missing the main point, I did not say that 5 was the answer.
First of all, you have to agree that
2^3 * 3^2 * 5^1 = 360
now match (a^m)(b^n)(c^r) with 2^3 * 3^2 * 5^1
clearly:
a = 2
b = 3
c = 5
m = 3
n = 2
r = 1
then a+b+c-mnr
= 2+3+5 - 3(2)(1)
= 10 - 6
= 4
    
First of all, you have to agree that
2^3 * 3^2 * 5^1 = 360
now match (a^m)(b^n)(c^r) with 2^3 * 3^2 * 5^1
clearly:
a = 2
b = 3
c = 5
m = 3
n = 2
r = 1
then a+b+c-mnr
= 2+3+5 - 3(2)(1)
= 10 - 6
= 4
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