You know the initial vertical velocity (35sin35).
Vf at top max height is zero. Use
vf=vivertical-gt to to find the time to the top, then use
h=ho+vivert*t-1/2 g t^2 to find the max height.
For time of flight, hf=0
0=ho+vivert*t-gt solve for t
now, having the time of flight, the horizontal distance will be
distance=vihoriz*t
A troll on a 75m tall cliff throws a 35 m/s boulder at 35 degrees above the horizontal at a herd of sheep. What is the time of flight, the range and the maximum height for the boulder?
HOW DO I DO THIS??
2 answers
is the correct answer for max height 20.58, and the correct answer for the range 58.77?