Asked by Animesh
if x is directly proportional to 6 more than the cube of y and x is 28 when y is 2, what is the value of y when x is 140?
Answers
Answered by
bobpursley
x=k(y^3+6)
28=k(8+6) or k= 2
140=2y^3+12
y^3=64
y=4
28=k(8+6) or k= 2
140=2y^3+12
y^3=64
y=4
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