Asked by pb

two pump can individual fill the tank in 10 hours and 12 hours respectively while a third pump empites the full tank in 20 hours.If all the three pump are run simultaneously,in how munch time will be the tank be filled?
Answered by Steve
1/x = 1/10 + 1/12 - 1/20
x = 15/2
Answered by John
12/120 + 10/120 - 6/120

16/120 = 1/x

120/16 = x

15/2 =x
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