Question

An athlete finished the 100 meter race in 10sec. What was his average speed? acceleration? Acceleration time? Acceleration distance

Help with few questions already got the
already got the first two

V=d/t
=100m/10s
=10m/s

and

Acceleration= Vf-Vi/t
=10m/s-0/10s
=10m/s^2

how to find the other two, the acceleration time and the acceleration distance? please help

Answer 1

The teacher also give the athlete's top speed to be 12m/s, dunno if this will be helpful, but still need to reconsider I guess

Answer 2

He clearly did not accelerate at 10 m/s^2 for the whole 10 seconds, or the distance covered would have been 1/2 at^2 = 500m and his top speed would have been 100m/s.

So, if he accelerated smoothly from 0-12 m/s over t seconds, then a = 12/t m/s^2

So we have

(1/2)(12/t)t^2 + 12(10-t) = 100
6t+120-12t = 100
-6t = -20
t = 10/3 s

He accelerated for 10/3 seconds at 18/5 m/s^2