Asked by Genga
Find the square root of the following by prime factorization 7056
Answers
Answered by
Steve
7056 = 2 * 3528 = 2^2 * 1714 = 2^3 * 857
Now factor 857. You know there are no more 2's in there, so start with 3, and so on.
So, what do you get? Since there are only three 2's, the square root will not be an integer, but will have a radical left over.
Now factor 857. You know there are no more 2's in there, so start with 3, and so on.
So, what do you get? Since there are only three 2's, the square root will not be an integer, but will have a radical left over.
Answered by
Reiny
7056 = (2*2*2*2)*(3*3)*(7*7)
= 16*9*49
so √7056 = 4*3*7 = 84
= 16*9*49
so √7056 = 4*3*7 = 84
Answered by
Steve
I see I can neither factor nor count. Go with Reiny.