Asked by Om Gopal Mishra
A 0.10 kg of steel ball falls on earth from a height of 10 m and bounces to a height of 1.0m . Let all the dissipated energy were absorbed by the ball as heat, calculate the rise in temperature if specific heat capacity of is 0.12 cal/g/deg C.
Answers
Answered by
bobpursley
energy from falling: mgh=.1*9.8*10
energy to get to 1m= mgh=.1*9.8*1
subtract those, and you get heat energy.
Heatenergy=m*c*Changtemp
solve for changeIntemp
energy to get to 1m= mgh=.1*9.8*1
subtract those, and you get heat energy.
Heatenergy=m*c*Changtemp
solve for changeIntemp
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