ave speed is half of max ... 1.70 rad/s
stopping time ... 2.50 π rad / 1.70 rad/s
ang acc ... 3.40 rad/s / stopping time
A wheel has an initial velocity of 3.40rad/s and it rotates 1.25 revolutions before stopping
what is the angular acceleration of the wheel
how long does it take for the wheel to come to rest
2 answers
1.25 revolutions = 3.93 radians
2(a)(S)= wf^2 - Wi^2
2 (a)(3.93) = 0^2 - (3.40)^2
7.85a = -11.56
a = -1.472 rad/s/s
So
wf = wi +at
0 = 3.40 - 1.472t
t = 2.3 s
2(a)(S)= wf^2 - Wi^2
2 (a)(3.93) = 0^2 - (3.40)^2
7.85a = -11.56
a = -1.472 rad/s/s
So
wf = wi +at
0 = 3.40 - 1.472t
t = 2.3 s
2 answers