Asked by Riley
A wheel has an initial velocity of 3.40rad/s and it rotates 1.25 revolutions before stopping
what is the angular acceleration of the wheel
how long does it take for the wheel to come to rest
what is the angular acceleration of the wheel
how long does it take for the wheel to come to rest
Answers
Answered by
Scott
ave speed is half of max ... 1.70 rad/s
stopping time ... 2.50 π rad / 1.70 rad/s
ang acc ... 3.40 rad/s / stopping time
stopping time ... 2.50 π rad / 1.70 rad/s
ang acc ... 3.40 rad/s / stopping time
Answered by
M@S
1.25 revolutions = 3.93 radians
2(a)(S)= wf^2 - Wi^2
2 (a)(3.93) = 0^2 - (3.40)^2
7.85a = -11.56
a = -1.472 rad/s/s
So
wf = wi +at
0 = 3.40 - 1.472t
t = 2.3 s
2(a)(S)= wf^2 - Wi^2
2 (a)(3.93) = 0^2 - (3.40)^2
7.85a = -11.56
a = -1.472 rad/s/s
So
wf = wi +at
0 = 3.40 - 1.472t
t = 2.3 s
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