A 100tones acts on a 300tones block placed on an

Question

inclined plan with a 3:4 slope, the coefficients of
frictions btw the blocks and the inclined plane are 0.25
and 0.20 respectively
(A) determine weather the block is in equilibrium
( if the block is not in equilibrium, find the enforce on the block
(C) if the block is not in the equilibrium, find the
acceleration
Show working need help

Answer 1

a. force down the slope:
first, the slope. I do not know what you mean by 3:4 slope, nowdays we refer to slope as a fraction, rise/run . If you mean it rises 3 units for each horizontal run of 4, then we say slope of 3/4.
In that case, we commonly figure the angle with that slope, in this case we know the right triangle, 3,4,5.
so tangentTheta=3/4; sinTheta=3/5, and cosineTheta=4/5

Now, force down the hill due to gravity:
weight*sinTheta=300*3/5 tons
force up hill due to acting force=100 tons
friction up hill=weight*mu*cosTheta=300*.25*4/5
=1200/20=60
Net force down= 300*3/5 -100-60=20 tons (check the math)

accelerationi:
a= netforce/total mass=20/300
net force down=down-up=180-100=80 down

Answer 2

c. above needs tuning. Mass must be in mass units, I assume your tons unit was weight, so figure mass for 100 tons weight.