Asked by Bom B
                Two planes start at 11AM from two airports 1800 miles apart, and fly toward each other at average rates of 200 and 250 miles per hour. the time at which they pass each other will be?
(A)4:30 PM
(B)2:30 PM
(C)2 PM
(D)3 PM
            
            
        (A)4:30 PM
(B)2:30 PM
(C)2 PM
(D)3 PM
Answers
                    Answered by
            unowen
            
    Let n be the time between the planes leaving and then meeting each other. Then
200n+250n=1800
450n=1800
n=4 hours
☺☺☺☺
    
200n+250n=1800
450n=1800
n=4 hours
☺☺☺☺
                    Answered by
            chloe
            
    d 3pm. 
the guy (unowen) above me did it correctly but forgot that it was asking for the time the planes met. 4 hours added onto 11 am is 3pm, thus answer choice d
    
the guy (unowen) above me did it correctly but forgot that it was asking for the time the planes met. 4 hours added onto 11 am is 3pm, thus answer choice d
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