Asked by Anonymous
                what is the time necessary for 99.9%of the atoms of a radioactive compound to be disintegrated? t½=5times.
            
            
        Answers
                    Answered by
            bobpursley
            
    .001=e^-.692t
where t is in halfflives...
ln(.001)=.692t
-6.91=-.692t
t=10 halflives...
Lets look at five halfflives...
xxx=e^-.692*5
xxx= 0.031429762 or .97 is gone in five halflives...
    
where t is in halfflives...
ln(.001)=.692t
-6.91=-.692t
t=10 halflives...
Lets look at five halfflives...
xxx=e^-.692*5
xxx= 0.031429762 or .97 is gone in five halflives...
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