Asked by Gly
Find the arithmetic sequence whose 1st term is 1 and the 1st, 2nd and 6th terms form a geometric sequence
Answers
Answered by
Scott
1 / (d + 1) = (d + 1) / (5d + 1)
5d + 1 = (d + 1)^2 ... d^2 - 3d = 0 ... d = 3
An = 3n - 2
5d + 1 = (d + 1)^2 ... d^2 - 3d = 0 ... d = 3
An = 3n - 2
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