Asked by Charlie
How large a pressure increase (in ATM) must be applied to water if it is to be compressed in volume by 1%? The bulk modulus of water is 2 ~ 10^9 N/m^2 and 1 ATM = 10^5 N/m^2
I think that it is
P = bulk modulus * 0.01
because 1/100 = 0.01, which is 1% of a volume.
B = ĢP/ [(ĢV/Vi)] < --- I found this equation.
I think that it is
P = bulk modulus * 0.01
because 1/100 = 0.01, which is 1% of a volume.
B = ĢP/ [(ĢV/Vi)] < --- I found this equation.
Answers
Answered by
bobpursley
Correct.
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