Asked by scienceguy
The relative molecular mass of calcium carbonate (CaCO3) is 100. What is the minimum volume of 2.0 M hydrochloric acid (HCl) that would be needed to completely react with 2.0 g of calcium carbonate?
Answers
Answered by
bobpursley
CaCO3 + 2HCl > CaCl3 + CO2 + H2O
2grams/100= .02 moles
so you need .04 moles HCl
molesHCl=volume*Molarity
volume = .04/2= .02 liters or 20 ml
2grams/100= .02 moles
so you need .04 moles HCl
molesHCl=volume*Molarity
volume = .04/2= .02 liters or 20 ml
Answered by
ddval
Thanks! Bob
Answered by
Anonymous
Wow love u all
Answered by
Anonymous
Thanks alot
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