Asked by scienceguy
                The relative molecular mass of calcium carbonate (CaCO3) is 100. What is the minimum volume of 2.0 M hydrochloric acid (HCl) that would be needed to completely react with 2.0 g of calcium carbonate?
            
            
        Answers
                    Answered by
            bobpursley
            
    CaCO3 + 2HCl > CaCl3 + CO2 + H2O
2grams/100= .02 moles
so you need .04 moles HCl
molesHCl=volume*Molarity
volume = .04/2= .02 liters or 20 ml
    
2grams/100= .02 moles
so you need .04 moles HCl
molesHCl=volume*Molarity
volume = .04/2= .02 liters or 20 ml
                    Answered by
            ddval
            
    Thanks! Bob 
    
                    Answered by
            Anonymous
            
    Wow love u all
    
                    Answered by
            Anonymous
            
    Thanks alot
    
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