Asked by Kelsey

When calcium iodate is added to water at 25 degrees Celsius, the equilibrium concentration of calcium ion was found to be 0.011M. Calculate the value of Ksp for this salt.

Answers

Answered by DrBob222
.......Ca(IO3)2 ==> Ca^2+ + 2IO3^-
I......solid.........0.......0
C......solid.........x.......2x
E......solid.........x.......2x

Ksp = (Ca^2+)(IO3^-)^2
Ksp = (x)(2x)^2 = 4x^3 and the problem tells you x is 0.11M. Substitute and solve for Ksp.
Answered by Justin
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