Asked by Franklin
For How Long Must A Current Of 1.5 Ampere Be Passed Through An Aqueous Solution Of A Copper Salt During Electrolysis In Order To Deposit 2.50g Of Copper (cu=63.5)
Answers
Answered by
DrBob222
96,485 coulombs of electricity will deposit 63.5/2 or 31.25 g Cu.
Coulombs = amperes x seconds.
How many coulombs must you have? That's
96,485 x 2.5 g/31.25 g = ?
Then ? coulombs = 1.5 x seconds. You know coulombs and amperes. Solve for seconds. Post your work if you get stuck.
Coulombs = amperes x seconds.
How many coulombs must you have? That's
96,485 x 2.5 g/31.25 g = ?
Then ? coulombs = 1.5 x seconds. You know coulombs and amperes. Solve for seconds. Post your work if you get stuck.
Answered by
James
576.5g
Answered by
Ummy
For how long a current of 1.5 ampere will be passed through an aqueous solution if copper salts during electrolysis in order to deposits 2.50g of copper ( cu=63.5)
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