Asked by Mark
how many different 5 player teams can be chosen from eight players? What formula do I use to solve this?
Answers
Answered by
MathMate
The number of combinations can be found from the formula
C(n,r)=n!/(r!(n-r)!)
n=total number of distinct objects
r=size of sample
For example,
there are 9 different fruits to choose from. The number of different samples of 6 fruits is equal to C(9,6)=9!/(6!(9-6)!)
=84
C(n,r)=n!/(r!(n-r)!)
n=total number of distinct objects
r=size of sample
For example,
there are 9 different fruits to choose from. The number of different samples of 6 fruits is equal to C(9,6)=9!/(6!(9-6)!)
=84
Answered by
Mark
C(8,5)=8!/(5!(8-5)!) So do I * these numbers next to come up with the answer I got 120
Answered by
MathMate
Yes, basically that, but watch out for parentheses and order of operations.
Examples:
C(8,5)=8!/(5!(8-5)!)
=40320/(120*6)
=56
and
C(9,6)=9!/(6!(3!))
=362880/(720*6)
=84
Examples:
C(8,5)=8!/(5!(8-5)!)
=40320/(120*6)
=56
and
C(9,6)=9!/(6!(3!))
=362880/(720*6)
=84
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