Asked by Rahat

In a past presidential election, it was estimated that the probability that the Republican candidate would be elected was 1/3, and therefore the probability that the Democratic candidate would be elected was 2/3 (the two Independent candidates were given no chance of being elected). It was also estimated that if the Republican candidate were elected, the probability that a conservative, moderate, or liberal judge would be appointed to the Supreme Court (one retirement was expected during the presidential term) was 1/6, 1/6, and 2/3, respectively. If the Democratic candidate were elected, the probabilities that a conservative, moderate, or liberal judge would be appointed to the Supreme Court would be 2/9, 5/9, and 2/9, respectively. A conservative judge was appointed to the Supreme Court during the presidential term. What is the probability that the Democratic candidate was elected? (Round your answer to three decimal places.)

Answers

Answered by MathMate
Events:
R=Republican candidate elected
D=Democratic candidate elected
C=conservative judge appointed
M=moderate judge appointed
L=liberal judge appointed

P(R)=1/3
P(D)=1-1/3=2/3
P(C|R)=1/6
P(M|R)=1/6
P(L|R)=2/3
P(C|D)=2/9
P(M|D)=5/9
P(L|D)=2/9

Need to find P(D|C)
or probability of Democratic candidate elected given a conservative judge was elected.

Again, use total probability and then Bayes theorem.

Please attempt the problem, and post what you have.

Answered by titi
i am unaware of what formula to use to solve this
Answered by MathMate
It will be similar to the previous problem.
http://www.jiskha.com/display.cgi?id=1498184495
Answered by MathMate
or the previous problem:
http://www.jiskha.com/display.cgi?id=1498438280

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