Asked by General Batman
What would be the correct way to arrange this?
Consider the reaction below.
3K2C2O4(aq)+2Fe(NO3)3(aq)->Fe2(C2O4)3(s)+6KNO3(aq)
What mass in grams of K2C2O4 (MM=166.22g/mole)will react completely with 35.0mL of 0.800M Fe(NO3)3?
Consider the reaction below.
3K2C2O4(aq)+2Fe(NO3)3(aq)->Fe2(C2O4)3(s)+6KNO3(aq)
What mass in grams of K2C2O4 (MM=166.22g/mole)will react completely with 35.0mL of 0.800M Fe(NO3)3?
Answers
Answered by
DrBob222
mols Fe(NO3)3 = M x L = ?
Convert mols Fe(NO3)3 to mols K2C2O4 using the coefficients in the balanced equation.
Then grams K2C2O4 = mols x molar mass = ?
Convert mols Fe(NO3)3 to mols K2C2O4 using the coefficients in the balanced equation.
Then grams K2C2O4 = mols x molar mass = ?
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