Asked by Rey
A block of mass 2 kg attached to a spring lies on a flat surface. When the block is pulled 5 cm to the right a force with a magnitude of 300 N is need to hold it in place. What is the work done by the spring when the block moves from x = 10 cm to x = 12 cm. Express your answer in joules.
Answers
Answered by
bobpursley
k=300N/.05m=6000 N/m
work done= PEmax-PEmin
= 1/2 k (.12^2-.10^2)
work done= PEmax-PEmin
= 1/2 k (.12^2-.10^2)
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