Asked by Sylvia
Find the roots using quadratic formula
1. X^2+7x =4
2. 4x^2 - 4x +1=0
1. X^2+7x =4
2. 4x^2 - 4x +1=0
Answers
Answered by
Reiny
I will do the first, then you show me how you did the second.
x^2 + 7x = 4
x^2 + 7x - 4 = 0
a = 1, b = 7, c = -4
x = (-b ± √(b^2 - 4ac) ) / (2a)
= (-7 ± √(49 - 4(1)(-4))/2
= (-7 ± √65)/2
x^2 + 7x = 4
x^2 + 7x - 4 = 0
a = 1, b = 7, c = -4
x = (-b ± √(b^2 - 4ac) ) / (2a)
= (-7 ± √(49 - 4(1)(-4))/2
= (-7 ± √65)/2