Asked by No name
A hot-air balloon ascends at the rate of 12m/s when it is 80m above the ground at which time a package is dropped over the side .
(a) how long would the package take to reach the ground ?
(b) with what speed would it hit the ground?
(a) how long would the package take to reach the ground ?
(b) with what speed would it hit the ground?
Answers
Answered by
bobpursley
No name: ARe you looking for answers to turn in and don't wnat your teacher to know? That is rather gutless.
hf=hi+vi*t+1/2 g t^2
0=80+12m/s*t-4.9t^2
solve for time t, with the use of the quadratic equation.
Speed:
Initial PE+initial KE= finalKE
mg*80+1/2 m 12^2 = 1/2 m vf^2
solve for vfinal, vf
hf=hi+vi*t+1/2 g t^2
0=80+12m/s*t-4.9t^2
solve for time t, with the use of the quadratic equation.
Speed:
Initial PE+initial KE= finalKE
mg*80+1/2 m 12^2 = 1/2 m vf^2
solve for vfinal, vf
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