c. A 2 kg block of ice has been stored in a chiller at a constant 0°C. In order to carry out an investigation, the block of ice needs to be turned into water at a temperature of 75°C.

Question

c.	A 2 kg block of ice has been stored in a chiller at a constant 0°C. In order to carry out an investigation, the block of ice needs to be turned into water at a temperature of 75°C.

Calculate how much heat energy is required to change the block of ice into water at 75°C. Assume the specific heat capacity of water is 4200 KJ/kg°C and the specific latent heat of fusion of water is 334 KJ/kg°C.

Kabir · Answer

The total heat energy is the heat energy required to change ice to water, plus the energy to bring water from 0C to 75C.

a) Specific latent heat of fusion of water (per kg) = 334kJ
Heat required for two kgs = 334 x 2 = 668kJ

b) Heat for temp. change = C x M x (Difference in temperature)
= 4200kJ x 2 x 75

Add parts (a) and (b), and you'll get your answer

Scott · Answer

the 4200 should be Joules, NOT kJ

bobpursley · Answer

I agree with Scott, the specific heat of water is 4.18Kj/Kg (or aboaut 4.2kg/kg so that heat would be 4.2kg/kg*2kg*75, that then is added to the heat of fusion (melting).