Question

How many grams of steam at 100C must be mixed with 200g of water at 20C in order for the equilibrium temperature to be 50C?
the sume of heats is zero...

Heat to heat water + heat or condense steam+heat to cool steam=0

200*cw*(50-20)+Hv*m + m*Cw*(50-100)=0
solve for mass m.

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