Asked by Clary F.
Tickets are drawn to determine first prize money is s100, 000. Each succeeding prize paid 60% as much as the ticket before it. What was the prize money for the 6th ticket drawn? Use the appropriate formula.
Answers
Answered by
Kabir
The formula you're going to use for this is as follows:
Initial Prize Money x (1 + Fraction of increase)^(ticket number - 1)
=> I'll represent 60% as 0.6
=> So, the answer is 100,000 x (1.60)^6, which you can solve.
Initial Prize Money x (1 + Fraction of increase)^(ticket number - 1)
=> I'll represent 60% as 0.6
=> So, the answer is 100,000 x (1.60)^6, which you can solve.
Answered by
Kabir
I'm sorry, I misread the question as '60% more than the one before it.'
The answer above is incorrect, I'll update the answer
The answer above is incorrect, I'll update the answer
Answered by
Kabir
Instead of
100,000 x (1.60)^6
It'll be
100,000 x (0.60)^6
100,000 x (1.60)^6
It'll be
100,000 x (0.60)^6
Answered by
Reiny
1st prize = 100,000
2nd prize = (.6)(10,000) = 6,000
3rd prize = (.6)^2 (10000) = 3600
...
6th prize = (.6)^5 (10,000) = .....
2nd prize = (.6)(10,000) = 6,000
3rd prize = (.6)^2 (10000) = 3600
...
6th prize = (.6)^5 (10,000) = .....
Answered by
Kabir
Ah, misread the question and then accidentally put a 6 in place of a 5
Thanks for the correction
Thanks for the correction
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