Asked by Prabin
The volume of co2 gas produced at NTP when 25 gram of caco3 is heated
Answers
Answered by
Damon
22.4 liters/mol
calcium carbonate is 100 g/mol
so we have 1/4 mol
(1/4)(22.4) = 5.6 liters = .0056 m^3
calcium carbonate is 100 g/mol
so we have 1/4 mol
(1/4)(22.4) = 5.6 liters = .0056 m^3
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