Question
A body of mass 10kg is moving with velocity 10m/sec.The work done to stop the body is :
A) 500J B)-500J C)1000J D)-1000J
How to calculate the answer?
A) 500J B)-500J C)1000J D)-1000J
How to calculate the answer?
Answers
MathMate
The kinetic energy of a body of mass m=10kg moving at v=10m/s is
E=(1/2)mv²
After being stopped, the kinetic energy of the body has been transferred to work done (assuming no frictional loss), and has nothing left.
So we can find
Work done=loss/reduction in kinetic energy.
E=(1/2)mv²
After being stopped, the kinetic energy of the body has been transferred to work done (assuming no frictional loss), and has nothing left.
So we can find
Work done=loss/reduction in kinetic energy.
Anurag
1000j
Anurag
500j
jannat
m=10kg,v=10m/s, ke=1/2×10×10×10=500
Ashutosh
500j