Asked by Anonymous


(need help with checking answers)

The height , h, in feet, of a bottle rocket is modeled by: h = -16t^2 + 60t

where t is the time in seconds.




A. Factor the expression.

H = 16t^2 +60 = 4(4t^2 + 15)

B. What is the height of the rocket after 2 seconds?


H = 4(4 times 2^2 + 15) = 4(16 + 15) = 128 ft


C. What is the height of the rocket after 3.75 seconds? Explain the solution.

4(4 times 3.75^2 + 15)

H(3.75) = 285

Answers

Answered by Steve
h = -16t^2 + 60t = 4t(-4t+15)

now work on B and C again.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions