Asked by Anonymous
(need help with checking answers)
The height , h, in feet, of a bottle rocket is modeled by: h = -16t^2 + 60t
where t is the time in seconds.
A. Factor the expression.
H = 16t^2 +60 = 4(4t^2 + 15)
B. What is the height of the rocket after 2 seconds?
H = 4(4 times 2^2 + 15) = 4(16 + 15) = 128 ft
C. What is the height of the rocket after 3.75 seconds? Explain the solution.
4(4 times 3.75^2 + 15)
H(3.75) = 285
Answers
Answered by
Steve
h = -16t^2 + 60t = 4t(-4t+15)
now work on B and C again.
now work on B and C again.
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