1. Explain why the function

f(x)=(x^2-4)/(x-2)
is not continous on [0,3]. what kind of discontinuity occurs?

2. use areas to show that

integral sign with the upper limit of 3 and a lower limit of 0 (x^2-4/x-2)dx=10.5

3. use the area to show that

intergral sign with the upper limit of 5 and a lower limit of 0 (int(x)dx)=10

1 answer

Please try first, ask us when you are stuck.
You know that when a denominator is zero there is trouble.
Simplify by factoring or whatever the expression inside before integrating.
I get 25/2 for integral from 0 to 5 of x dx. Graph of y = x is a triangle. The altitude is 5 and the base is 5.
Similar Questions
  1. What kind of discontinuity is this:F(x)= (2x^2 - 5x -3)/(x-3) if x does not equal 3 6 if x=3 It is a pieces use function. I
    1. answers icon 2 answers
  2. Supposeg(x) = { 1 / (x - 2) if x < 1 2x - 4 if x >/= 1 The best description concerning the continuity of g(x) is that the
    1. answers icon 1 answer
  3. Supposeg(x)={1/(x-2) if x<1 {2x-3 if x≥1 The best description concerning the continuity of g(x) is that the function: is
    1. answers icon 1 answer
  4. Supposeg(x)={1/(x-2) if x<1 {2x-4 if x≥1 The best description concerning the continuity of g(x) is that the function: is
    1. answers icon 0 answers
more similar questions