Asked by Angel
What are the solutions of the system?
y=x^2+3x-4
y=2x+2
a) (-3,6) and (2,-4)**
b) (-3,-4) and (2,6)
c) (-3,-4) and (-2,-2)
d) no solutions
y=x^2+3x-4
y=2x+2
a) (-3,6) and (2,-4)**
b) (-3,-4) and (2,6)
c) (-3,-4) and (-2,-2)
d) no solutions
Answers
Answered by
Damon
2x+2 = x^2 + 3x -4
x^2 + x - 6 = 0
(x-2)(x+3) = 0
x = +2 ---> y = 6 or (2,6)
x = -3 ---> y = -4 or (-3,-4)
so I disagree with you
x^2 + x - 6 = 0
(x-2)(x+3) = 0
x = +2 ---> y = 6 or (2,6)
x = -3 ---> y = -4 or (-3,-4)
so I disagree with you
Answered by
Steve
You got x = -3,2 correct, but your final answer is wrong.
Answered by
Angel
My secon guess was C
Answered by
Damon
guess? No need to guess !!!!
Answered by
Angel
So am I right or wrong
I suck at this
I suck at this
Answered by
Damon
which one is
(-3,-4) and (2,6) ?????
(-3,-4) and (2,6) ?????
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