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A heavy metal beam AB of mass 25Kg is supported at its ends.The beam carries a mass of 150Kg at a distance of 0.75m from end A.If the beam is 2m long, determine the thrust A and B.
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MathMate
A------m--M-----------B
0.75
M=25kg
m=150kg
Distance AM=2.0/2=1.0 m
Take moments about A:
(counter-clockwise positive)
B*2-150*0.75-25*1.0=0
B=(150*0.75+25)/2=137.5/2=68.75 kg
The reaction (thrust) at A can be found by summing vertical forces and equating to zero, or similarly taking moments about B.
0.75
M=25kg
m=150kg
Distance AM=2.0/2=1.0 m
Take moments about A:
(counter-clockwise positive)
B*2-150*0.75-25*1.0=0
B=(150*0.75+25)/2=137.5/2=68.75 kg
The reaction (thrust) at A can be found by summing vertical forces and equating to zero, or similarly taking moments about B.
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