Asked by sarah
A painter leans a 15 ft ladder against a house. The base of the ladder is 5 ft from the house. a) To the nearest tenth of a foot, how high on the house does the ladder reach? b) The ladder in part (a) reaches too high on the house. By how much should the painter move the ladder's base away from the house to lower the top by 1 ft?
Answers
Answered by
Reiny
You must be studying the Pythagorean Theorem.
Did you make a diagram?
make the ladder the hypotenuse of 15, the height as h, and the base as 5
then solve h^2 + 5^2 = 15^2
b) take the answer from a), reduce the height by 1 and do a new equation.
(I got a base of 14.555 for b) )
Did you make a diagram?
make the ladder the hypotenuse of 15, the height as h, and the base as 5
then solve h^2 + 5^2 = 15^2
b) take the answer from a), reduce the height by 1 and do a new equation.
(I got a base of 14.555 for b) )
Answered by
Reiny
oops
I checked my math again and that final answer should have been 7.23 ft, not 14.555
I checked my math again and that final answer should have been 7.23 ft, not 14.555
Answered by
Anonymous
8-foot ladder leaning a wall and make 53 degree angle
Answered by
jesus
pretty sure the answer is MILK
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