Asked by samuel
From point AandB on level ground,the angle of elevation of the top of a building are 25degree and 37degree respectively.if |AB|〓57m,calculate,to the nearest metre,the distances of the top of the building from AandB if they are both on thesame side of the building.
Answers
Answered by
Damon
Call T the top
call G the bottom
T G B is a right triangle
37 at B, 90 at G, thus 53 at BTG
TGA is a right triangle
25 at A, 90 at G, thus 65 at ATG
thus 122 at ABT
law of sines:
sin 25 / BT = sin 12/ 57
so BT = 156 meters (first answer)
now angle ABT = 180 - 12 - 25
= 143
so
sin 143 /AT = sin12/57
AT = 164 meters, second answer
call G the bottom
T G B is a right triangle
37 at B, 90 at G, thus 53 at BTG
TGA is a right triangle
25 at A, 90 at G, thus 65 at ATG
thus 122 at ABT
law of sines:
sin 25 / BT = sin 12/ 57
so BT = 156 meters (first answer)
now angle ABT = 180 - 12 - 25
= 143
so
sin 143 /AT = sin12/57
AT = 164 meters, second answer
Answered by
Damon
thus 143 at ABT see a few lines down
Answered by
Steve
if you don't like the law of sines, just study the tan/cot functions. You can easily see that the height h can be found from
h cot25° - h cot37° = 57
h cot25° - h cot37° = 57
Answered by
Anesu Emmanuel Mutonhodza
25+37
= 62
= 62
Answered by
Anonymous
Plz solve
Answered by
Fiyin
How do u get 122
Answered by
Sunday peace
That is called mathemagic
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