Asked by Neha
The mass of sodium carbonate required to prepare 250ml of 0.4N solution is
Answers
Answered by
DrBob222
Technically, one can't calculate this BECAUSE there is no reaction given; however, we usually assume, when the reaction isn't given, to use total + or - charge. That is 2 in this case; therefore,
mL x N x mew = grams where mew is milliequivalent weight.
equivalent weight then is molar mass/2 = 106/2 = 53 and mew is 0.053.Substitute mL, N, mew and solve for grams.
mL x N x mew = grams where mew is milliequivalent weight.
equivalent weight then is molar mass/2 = 106/2 = 53 and mew is 0.053.Substitute mL, N, mew and solve for grams.
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