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The mass of sodium carbonate required to prepare 250ml of 0.4N solution is
8 years ago

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DrBob222
Technically, one can't calculate this BECAUSE there is no reaction given; however, we usually assume, when the reaction isn't given, to use total + or - charge. That is 2 in this case; therefore,
mL x N x mew = grams where mew is milliequivalent weight.
equivalent weight then is molar mass/2 = 106/2 = 53 and mew is 0.053.Substitute mL, N, mew and solve for grams.
8 years ago

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