Question
How many different ways are there for an admissions officer to select a group of 7 college candidates from a group of 19 applicants for an interview?
Since the order in which they are picked does not matter, the number of combinations is 19!/(7!*12!)=
19*18*17*16*15*14*13/(2*3*4*5*6*7) =?
(Do the numbers or use a hand calculator. Many have keys for the factorial (!) function.)
Since the order in which they are picked does not matter, the number of combinations is 19!/(7!*12!)=
19*18*17*16*15*14*13/(2*3*4*5*6*7) =?
(Do the numbers or use a hand calculator. Many have keys for the factorial (!) function.)