Question

Please help me with this, given that x^2y^2-3xy+4xy^3=5 find dy/dx by implicit differentiation

Answer 1

just remember to use the product rule. Also, dx/dx = 1

x^2y^2-3xy+4xy^3=5
2xy^2+2x^2yy' - 3y-3xy' + 4y^3+12xy^2y' = 0
y'(2x^2y-3x+12xy^2) = -2xy^2+3y-4y^3

y' =

-2xy^2+3y-4y^3
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2x^2y-3x+12xy^2