Question
Could someone check these? basic honors algebra 1 question
of eight students in a class three will be chosen for student government positions. what is the number of permutations of those eight students to hold the three different positions?
24**
336
112
56
of eight students in a class three will be chosen for student government positions. what is the number of permutations of those eight students to hold the three different positions?
24**
336
112
56
Answers
MathMate
Can you explain <i>how</i> you got 24?
This permutation problem can be solved using the standard equation
P(n,r)=n!/(n-r)!
where
n=8, (8 candidates)
r=3 (three different positions out of n candidates)
Use your calculator to help you find the right answer.
Just in case, n!=1*2*3*4....*n
For example, 5!=1*2*3*4*5=120
This permutation problem can be solved using the standard equation
P(n,r)=n!/(n-r)!
where
n=8, (8 candidates)
r=3 (three different positions out of n candidates)
Use your calculator to help you find the right answer.
Just in case, n!=1*2*3*4....*n
For example, 5!=1*2*3*4*5=120
Steve
Think about it, and you will see that your answer is way off. At the very least, the fact that the question is asking about permutations should tip you off.
There are 8 ways to pick the first position.
For <u>each</u> of those 8 choices, there are 7 ways to pick the next one.
Similarly, there are 6 people left for the third pick.
This gives you 8P3 ways to choose. Now what do you say?
There are 8 ways to pick the first position.
For <u>each</u> of those 8 choices, there are 7 ways to pick the next one.
Similarly, there are 6 people left for the third pick.
This gives you 8P3 ways to choose. Now what do you say?
kel
Thank you guys. I understand now
kel
I multiplied 8*3, I see the answer is 336!
Damon
You better either read the chapter or Google permutations !
Damon
http://betterexplained.com/articles/easy-permutations-and-combinations/