Asked by Aryan Rajput
Sudha is twice as old as Garima.10 years ago Sudha was three times as old as Garima.Find Sudha's present.
Answers
Answered by
PsyDAG
S = 2G
S-10 = 3(G-10)
Substitute 2G for S in the second equation and solve for G. Insert that value into the first equation to solve for S. Check by putting both values into the second equation.
S-10 = 3(G-10)
Substitute 2G for S in the second equation and solve for G. Insert that value into the first equation to solve for S. Check by putting both values into the second equation.
Answered by
Vikas mishra
Let garima age be x year
And shudha age be 2x
And 10 year ago,garima age be (x-10)
10 year ago,shudha age be (2x-10)
Then a/q,
(X-10)=3(2x-10)
X-10=6x-30
X-6x=-30+10
-5x=-20
x=-20/-5
x=4
Hence,the garima age be 4 years
And the shudha age be 2x=2×4=8 years.
And shudha age be 2x
And 10 year ago,garima age be (x-10)
10 year ago,shudha age be (2x-10)
Then a/q,
(X-10)=3(2x-10)
X-10=6x-30
X-6x=-30+10
-5x=-20
x=-20/-5
x=4
Hence,the garima age be 4 years
And the shudha age be 2x=2×4=8 years.
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