If tan A=a/b prove that 2sec theta + 1/ cos theta+2=Õ a2+b2/b

Answer 1

I will assume that A and θ are the same

Draw a triangle. The legs are a and b, so the hypotenuse is √(a^2+b^2)

Now you know that secθ = 1/cosθ = √(a^2+b^2)/b

I expect you can handle the rest of the algebra...

Answer 2

Please put solution clearly now